Help me with Algebra!!!

Question

Use any division method you prefer and determine the following>>> A rock is tossed up at 20 m/s. The height of the rock after T seconds is h(T)=-9.8T^2+20T+1. What is the height of the rock after 2 seconds? Show all math steps to the solution.

Answer 1

The function h(T)=-9.8T^2+20T+1 describes the height of the rock at any given time T. So, to find the height of the rock at 2 seconds, we just need to plug in 2 for T and simplify.

h(T)= -9.8T^2+20T+1

h(2) = -9.8(2)^2+20(2)+1

h(2) = -39.2+40+1

h(2) = 0.8+1

h(2) = 1.8

So, the height of the rock at 2 seconds is 1.8 meters.