What is the tangent of the standard position angle if its terminal side intersects the unit circle at the point (-0.57,-0.82)? In which quadrant does this point lie?

Question

A) tan(θ)=-0.57 in quadrant 3

B) tan(θ)=-0.82 in quadrant 3

C) tan(θ)≈1.44 in quadrant 3

D) tan(θ)≈1.44 in quadrant 1

Answer 1

Given the point (-0.57,-0.82), we know that it is located in quadrant 3.

Tan(θ)=opp/adj=y/x=-.82/-.57≈1.44

Answer is C