Given: r=6•sinθ
We have to test it in three ways. If the equation is the same as the given after substitution, then the equation is symmetric with respect to the following axis:
(1) Symmetry on polar axis (x-axis): replace θ with -θ
Original: r=6•sinθ
substitution:
r=6•sin(-θ)
r=-6•sin(θ) not the same as the original.
(2) Symmetry on θ=π/2 (y-axis): replace θ with -θ and replace r with -r
substitution:
-r=6•sin(-θ)
-r= -6•sin(θ)
r=6•sin(θ) the same as the original
(3) Symmetry on the pole (r): replace r with -r
Substitution:
-r= 6•sin(θ) not the same as the original
Therefore, it is symmetric with respect to θ=π/2.