Write the equation in standard form for the ellipse with foci (– 14, 4+ \sqrt(82)) and (– 14,4– \sqrt(82)) and vertices ( – 14,15) and ( – 14, – 7).

Answer 1

2a = 15 + 7 = 22; a = 11; 2c = 2sqrt(82); c = sqrt(82); b² = a² - c² = 121 - 82 = 39; center at point (- 14, 4).

Equation of ellipse (y - 4)²/121 + (x + 14)²/39 = 1