If the first term of an arithmetic sequence is -0.8 and the common differences 2.6 what term has a value of 98?

Answer 1

For an arithmetic sequence,

a_n = a₁+d(n-1)

a₁=-0.8 and d = 2.6

98 = -0.8 + 2.6(n-1) = -0.8+2.6n -2.6

Solve for n

2.6 n = 98+0.8+2.6 = 101.4

n=101.4/2.6 = 39

The 39th term has the value of 98.