Write a quadratic equation that passes through a vertex of (−3,2) and the point (−1,−10)

Question

Write a quadratic equation that passes through a vertex of (−3,2) and the point (−1,−10)

please answer so i can check my answer

Answer 1

ax^2+bx+c->vertex form->a(x-h)^2+k where (h,k) is the vertex. so f(x)=a(x--3)^2+2->f(x)=a(x+3)^2+2 and then put in the point f(x)=a(x+3)+2-> -10=a(-1+3)+2=>-12=a(2)->-6=a

-6(x+3)^2+2=>-6(x^2+6x+9)+2->-6x^2-36x-54+2->-6x^2-36x-52 so -6x^2-36x-52 is the quadratic equation from this.

Answer 2

y = C(x+3)^2 + 2

-10 = C(-1+3)^2 + 2

-10 = C(2)^2 + 2

-10 = 4c + 2

-12 = 4c

c = -3

y = -3(x+3)^2 + 2