Can you help me with this explain question. 16^(2x-3)=4^(x)

Question

This type of log equation can be approached in multiple ways. Do you expect the answer to be the same for each way? Now solve in two different ways.

(I don't understand what are the two different ways to solve this question?)

Answer 1

16^{2x - 3} = 4^x; 4^{2(2x - 3)} = 4^x; 4x - 6 = x; 3x = 6; x = 2