Eric H. answered 04/12/21
Math student - love helping other students
Efef E.
asked 04/11/21growth and decay for algebra 2
Eric H. answered 04/12/21
Math student - love helping other students
Anonymous A. answered 04/11/21
A pre-student teacher with a passion for math!
Hi there,
Try using the following equation for continuous exponential growth:
P(t) = P0 ekt
where P0 is the initial amount, k is rate (in decimal form!), t is the amount of time that has passed (in this case, in years), and P(t) is the amount after t years.
From the prompt, we know
Now all you have to do is plug in the values in the appropriate places. So, we get
27,490 = 16,000e0.07t
Dividing both sides by 16,000, resulting in
(27,490/16,000) = e0.07t
To get t on its own, we'll have to get rid of that e. Take the natural log of both sides of the equation. We get
ln(27,490/16,000) = ln(e0.07t)
ln(27,490/16,000) = 0.07t
Divide both sides by 0.07. Plugging this into your calculator, you should get
t = 7.73 years
Hope this helps!
David D. answered 04/11/21
Science and Math Tutor with a PhD in Physics
Using the formula for exponential growth and decay we can solve this problem. The formula is P = P0ert where P0 is the initial value (16000), P is the final value (27490), r is the rate (7% or 0.07 growth per year), and t is the time in years. Plugging these numbers in we have the equation 27490 = 16000*e(0.07)t. We now need to solve for t, shown in the following steps:
Hello, Efef,
At the start (Year 0), the population is 16,000. The general formula for finding the population at any year, x, afterwards is:
(16,000)*(1.07)x
You can graph this equation or make a table, as I've done here:
It looks like 8 years is the correct number for the population to reach 2790. Off by 1, but I'll blame the census.
Bob
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