So, just like f(3) = 34 + 6, etc...
f(g(h(x))) = (√2 - 4)4 + 6 = (√2 - 4)(√2 - 4)(√2 - 4)(√2 - 4) = (2 - 8√2 +16)(2 - 8√2 + 16) = 4 - 16√2 + 32 + 16√2 - 128 + 128√2 + 32 - 128√2 + 256 = 196
Brianna W.
asked 03/26/21If f(x)=x^4+6, g(x)=x-4, and h(x)=Radical 2 then f(g(h(x)))
So, just like f(3) = 34 + 6, etc...
f(g(h(x))) = (√2 - 4)4 + 6 = (√2 - 4)(√2 - 4)(√2 - 4)(√2 - 4) = (2 - 8√2 +16)(2 - 8√2 + 16) = 4 - 16√2 + 32 + 16√2 - 128 + 128√2 + 32 - 128√2 + 256 = 196
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