Inactive Tutor answered 03/24/21
Change of base formula:
logxa = log10(a)/log10(x)
Therefore,
log42 = log10(2)/log10(4)
log48=log10(8)/log10(4)
replacing,
log42+log48 = log10(2)/log10(4) + log10(8)/log10(4)
using calculator:
Ans: 2
Ben A.
asked 03/24/21log42 + log48
Inactive Tutor answered 03/24/21
Change of base formula:
logxa = log10(a)/log10(x)
Therefore,
log42 = log10(2)/log10(4)
log48=log10(8)/log10(4)
replacing,
log42+log48 = log10(2)/log10(4) + log10(8)/log10(4)
using calculator:
Ans: 2
log42 + log48 = log416 = 2
Get a free answer to a quick problem.
Most questions answered within 4 hours.
Choose an expert and meet online. No packages or subscriptions, pay only for the time you need.