The sum of the ages of three brothers john,james and jack is 6yrs,james is twice as old as jack and one and a half times as old as john.Determine their ages

Question

Determine their present sges

Answer 1

x+y+z = 6

y=2z, z=y/2

x=John's age

y=James's age

z = Jack's age

y = (3/2)x, x=(2/3)y

(2/3)y + y + y/2 = 6

multiply by 6

4y + 6y + 3y = 36

13y = 36

y = 36/13 = 2 10/13 years old for James

x= (2/3)y= (2/3)(36/13) = 24/13 = 1 and 11/13 years old for John

z = y/2 = 36/13 = 18/13 = 1 5/13 years old for Jack

since we don't usually count parts of a year

they're 2 years & 9 months old for James, 1 year & 4 months old for Jack and

1 year and 10 months old for John

That's with partial months rounded down

2 yr 9 mo

1 yr 4 mo

1 yr 10 mo add to

5 yr 11 mo