For the point P(12, - 12) and Q(17, - 9) find the distance d(P, Q) and the coordinates of the midpoint M of the segment PQ

Answer 1

d^2 = 5^2 + 3^2 = 25+9 = 34

distance = sqr34 = about 5.831

midpoint = (x,y) = average of the x and y coordinates

x= (12+17)/2 = 29/2 = 14.5

y = (-9 -12)/2 = -21/2 = -10.5

midpoint is (14.5, -10.5)