
Alvin L.
asked 03/12/21The domain of h(x)=f(x)/g(x) is x≠2, x≠1. Which of the following are possible? Select all that apply. g contains the factor (x−2) f contains the factor (x−2) g(2)=0 g(−1)=0
More
1 Expert Answer
Raymond B. answered 08/20/23
Tutor
5
(2)
Math, microeconomics or criminal justice
g(x) = a(x-2)(x-1)
f(x) = (b)h(x)/(x-2)(x-1)
g(2) =0 = g(1)
but g(-1) may or may not =0, most likely it doesn't
Still looking for help? Get the right answer, fast.
Ask a question for free
Get a free answer to a quick problem.
Most questions answered within 4 hours.
OR
Find an Online Tutor Now
Choose an expert and meet online. No packages or subscriptions, pay only for the time you need.
Sean M.
a, b, and c are possible. The domain is a possible x values. that means you can't get an answer if you plug in 2 or 1. what can cause that? a demonimator that's zero or a negative square root. g containing x-2 would make sense (plug in 2 and you get 0). it doesn't matter what f is (as long as it's not a square root of a negative), so that's possible there. plugging in 2 into g should make the denominator 0, so g(2)=0 also makes sense. plugging in -1 to the denominator (g(x)) giving you a zero means that x/=-1. The question says 1, not -1. The only bad choice is d. All others are good03/18/21