There are 18 animals in the barn some are chickens and some are cows there are 58 legs in all

Answer 1

Using "x" represents chickens and "y" represents cows

x + y = 18 Total number of chickens and cows

2x + 4y = 58 Total number of legs of the animals combined

Solve using elimination

-2x - 2y = -36 (multiply the entire equation by -2 so the "x's" eliminate)

2x + 4y = 58

2y = 22

y = 11 (11 cows)

x + (11) = 18 (substitute number of cows into initial equation and find number of chickens)

x = 7 (7 chickens)

7 chickens and 11 cows

Answer 2

H+C = 18

2H+4C = 58

2H +2C= 36

2C = 22

C = 11 cows (no bulls?)

H=18-11 = 7 chickens (mostly hens, maybe a rooster or 2)

2(7)+4(11) = 14+44= 58 total legs