
Mark M. answered 03/12/21
Mathematics Teacher - NCLB Highly Qualified
x = (p-1(x) + 1)3 - 3
x + 3 = (p-1(x) + 1)3
3√(x + 3) = p-1(x) + 1
3√(x + 3) - 1 = p-1(x)
Abby B.
asked 03/12/21Let p(x)= (x+1)3-3. Write an equation for p-1
Mark M. answered 03/12/21
Mathematics Teacher - NCLB Highly Qualified
x = (p-1(x) + 1)3 - 3
x + 3 = (p-1(x) + 1)3
3√(x + 3) = p-1(x) + 1
3√(x + 3) - 1 = p-1(x)
to find the inverse switch pan dx and solve for p
x=(p+1)^+3
(x-3)= (p+1)^3
(x-3)^1/3 = p+1
p= (x-1)^1/3 -1
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