what is the equation of the directrix for the parabola -8(y-3)=(x+4)^2 ?

Question

a. y=5

b. y=1

c. y=-2

d. y=-6

Answer 1

y - 3 = (-1/8)(x + 4)²

y = (-1/8)(x + 4)⁴ + 3

y = k - p

y = 3 - p

p = 1/ 4a

p = 1 / 4(-1/8)

p = -2

y = 5