Hi Denise F.
10 puppies
20 kittens
70 turtles
You can use a system of equations and substitution to set up the problem in terms of one variable please see below
Let x = puppies
Let y = kittens
Let z = turtles
If there are twice as many kittens as puppies then
y = kittens = 2(puppies) = 2x
y = 2x
We can substitute 2x for y in our equations
For our Equations we have two
Total Stock Equation 1
x + 2x + z = 100
We know puppies cost 30 each, kittens cost $20 and turtles cost $5 each
Total Worth of stock Equation 2
30x + 20(2x) + 5z = 1050
When we combine like terms
Equation 1
3x + z = 100
with z = 100 -3x (this puts z in terms of x)
Equation 2
30x + 40x + 5z = 1050
70x + 5z = 1050
We now have two equations in two unknowns but we can again use substitution to put everything in terms of x in Equation 2
70x + 5(100 -3x) = 1050
70x + 500 - 15x = 1050
Combine like terms again
55x + 500 = 1050
Subtract 500 from both sides of the equation
55x = 550
Divide both sides by 55
x = 10
Since we already know from the previous substitutions
y = 2x = 20
z = 100 - 3x = 70
We have 10 puppies, 20 kittens and 70 turtles
Checking in the original equations
x + y + z = 10 + 20 + 70 = 100
30(10) + 20(20) + 5(70) = 300 + 400 + 350 = 1050
I hope this helps it can also be done by Elimination
Brenda D.
03/11/21
Denise F.
Thank you!03/11/21