Hi Mona H.
(18x - 6x2)/(3x - 9)
Factor out negative 6x from the numerator and positive 3 from the denominator
-6x(-3 + x)/3(x - 3) since
-3 + x = x - 3
-6x(x - 3)/3(x - 3)
The quantity (x - 3) cancels out as it is common to the numerator and denominator leaving
-6x/3 = - 2x
Hope this helps