what is the equation of a line through point (-4,5) that is perpendicular to the line with equality y=-6x+4?

Question

Please help

Answer 1

The slopes of perpendicular lines are negative reciprocals.  

 

The slope of the line y = -6x + 4 is -6.  So, any line perpendicular to that line has slope 1/6.

 

By the point slope form, an equation of the line with slope 1/6 and passing through the point (-4, 5) is:

 

y - 5 = (1/6)(x - (-4))

 

y - 5 = (1/6)x + 2/3

 

y = (1/6)x + 17/3