Write a polynomial in standard form with zeros −3, −6, and −1

Answer 1

(x+3)(x+6)(x+1) = (x^2+9x+18)(x+1) = x^3 +10x^2 + 27x + 18

Just take each zero and change its sign, then stick an x in front of it, to create 3 factors.

Answer 2

If a polynomial has zeros -3, -6 and -1, each zero is:

x = -3, x = -6, x = -1.

Moving the numbers to the left, you have x+3 = 0, x+6 = 0 and x+1 = 0.

To find the polynomial, multiply the 3 zeros. i.e.:

(x+3)(x+6)(x+1) = 0

This is because if x+3 = 0, then the whole equation becomes 0*(x+6)(x+1) =0 or 0=0.

For the algebra, first do 2 brackets, then the other one and, after a little work, you should have :