Raymond B. answered 08/20/23
Math, microeconomics or criminal justice
1/2 = e^5730r where r= annual decay rate, 5730 = t years for half life
take natural logs
ln.5 = 5730r
r = ln.5/5730=K= about 1.24x10^-4 = .000124 = .0124%
C(t) = (Co)(e^Kt
C(t) = (Co)(e^1.24tx10^-4
C(t) = Carbon at time t years
Co= amount of carbon when the organism dies = 1ppt
so
C(t) = e^1.24t(10^-4)