The critical issue here is that for a polynomial with real coefficients complex roots occur in conjugate pairs,
Therefore your equation is (x-3)(x+2+2i)(x+2-2i)=(x-3)(x2+4x+8).
I will leave the last multiplication to you!
Hayden J.
asked 03/05/21The critical issue here is that for a polynomial with real coefficients complex roots occur in conjugate pairs,
Therefore your equation is (x-3)(x+2+2i)(x+2-2i)=(x-3)(x2+4x+8).
I will leave the last multiplication to you!
Get a free answer to a quick problem.
Most questions answered within 4 hours.
Choose an expert and meet online. No packages or subscriptions, pay only for the time you need.