f(x)=x^2-x+3, g(x)=2x-1 find f(g(0))

Answer 1

g(0) = 2x0 - 1 = -1

f (g(0)) = f (-1) - (-1)² - (-1) + 3 = 1 + 1 + 3 = 5

Answer 2

f(x) = x² - x + 3,

g(x) = 2x - 1

g(0) = 2·0 - 1 = -1

f(g(0)) = f(-1) = ____?

Answer 3

So this is what is called a composite function and we're evaluating it at 0.

We evaluate these types of functions working our way from the inside to the outside.

Because it is written as f(g(0)) we first have to evaluate it using g(x) first since g is in the "inner" part of the function and f(x) surrounds it.

To evaluate the g function at 0 we must do g(0) = 2(0) - 1, substituting x for 0.

Doing so we get g(0) = 0 - 1 = -1

Now we must insert this value into the f function.

So, we do f(-1) = (-1)² - 1 + 3

f(-1) = 1 + 1 + 3

f(-1) = 5

So, f(g(0)) for this question would equal 5.