Question is in the desription

Question

The formula d=10log(I/I₀₎ can be used to understand how loud a sound is in decibels, given its intensity. Let loudness of a sound be d and I the physical intensity. Suppose the decibel level is 60. The physical intensity, I , is how many times that of I₀ ?

A 1,000,000

B 10,000,000

C 100,000

D 1,000

Answer 1

Substitute 60 in for d.

So, 60 = 10 log(I/I₀)

6 = log(I/I₀)

Log is base 10 so 10⁶ = I/I₀

Therefore I is 1,000,000 times I₀