Suselie M.

asked • 03/02/21

Please Help!! Use Descartes' rule of signs to help list the possibilities for the nature of the solutions for the equation. Do not solve the equation. (Select all that apply.) 6x2 − 12x + 2 = 0 2

Use Descartes' rule of signs to help list the possibilities for the nature of the solutions for the equation. Do not solve the equation. (Select all that apply.)

6x2 − 12x + 2 = 0

2 nonreal complex solutions

2 negative solutions

2 positive solutions

1 positive solution and 1 nonreal complex solution

1 negative solution and 1 nonreal complex solution

Please help me! anybody!?

1 Expert Answer

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Raymond B. answered • 03/02/21

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same as 3x^2-6x +1 = 0, after dividing by 2


the discriminant is b^2 -4ac = 36-4(3)(1) > 0, b=-6, a = 3, c = 1


when b^2-4ac > 0 there are two real solutions

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Suselie M.

Thank you so much!. I want to make sure I understand it. Which gives me 2 or 0 positives zeros and 0 negatives if I'm not mistaken. I got the answer correct its 2 nonreal complex solutions & 2 positive solutions for the selection that apply.
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03/03/21

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