x + 3y - z = 2
x + y - z =0
3x + 2y - 3z = -1
x=z+2-3y
x=z-y
z-y=z+2-3y
-y=2-3y
0=2-2y
-2=-2y
y=1
x+y-z=0
x+1-z=0
x+1=z
There is not enough information to answer this problem after that. Y is definitely 1, but x and z are any two numbers that are one away from each other. 9,1,10 works just as well as -5,1,-4