Hello, Ashton,
Nike D. has the correct answer (after you change y = 6.3x to y=5*3x).
You could also solve the equation directly:
100 = 6*3x
I get:
x = 2.58 weeks, unless anyone fishes, successfully, in that period.
Bob
Ashton F.
asked 02/24/21A fisherman illegally drops some fish into a pond, and they quickly propagate (reproduce). The population growth of the new specifies is modeled by P(x) = 6(b)^x, where x is the time in weeks following the moment he dropped the fish into the pond and b is a positive unknown base. Suppose that b is 3. Graph this relationship. How long does it take for there to be at least 100 fish in the pond?
Hello, Ashton,
Nike D. has the correct answer (after you change y = 6.3x to y=5*3x).
You could also solve the equation directly:
100 = 6*3x
I get:
x = 2.58 weeks, unless anyone fishes, successfully, in that period.
Bob
Mike D. answered 02/24/21
Effective, patient, empathic, math and science tutor
Well b=3. So P(x) = 6 . 3x
Graph this on Desmos (y = 6.3x) and also draw the line y=100
Where these two lines intersect read off the x value, that is the required answer
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Robert S.
02/24/21