Raymond B. answered 02/25/21
Math, microeconomics or criminal justice
L=5+2W
124 = 2L + 2W = 10+4W + 2W = 10 + 6W
6W = 124-10 = 114
W = 114/6 = 19 inches wide
L = 5 +2(19) = 38+5 = 43 inches long
43 by 19 inches
124= 2(43+19) = 2(62)= 124
Kryslin G.
asked 02/24/21the length of a rectangle is 5 more than double the width. If the perimeter is 124 inches, find the dimensions.
Raymond B. answered 02/25/21
Math, microeconomics or criminal justice
L=5+2W
124 = 2L + 2W = 10+4W + 2W = 10 + 6W
6W = 124-10 = 114
W = 114/6 = 19 inches wide
L = 5 +2(19) = 38+5 = 43 inches long
43 by 19 inches
124= 2(43+19) = 2(62)= 124
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