Consider the function: f ( x ) = − 2 x 2 − 4 x + 96

Question

Consider the function: 

Answer 1

find the zeroes by setting it = 0 and solve for x

2x^2 + 4x - 96= 0

x^2 + 2 - 48= 0

(x+8)(x-6) = 0

x = -8 and 6

vertex is half way between them or (6-8)/2 = x= -1

plug that into f(x) to get f(-1) = -2+4+96 = 98

vertex is the maximum point of the downward opening parabola = (-1, 98)

y intercept = (0,96)