
Patrick B. answered 02/21/21
Tutor
4.7
(31)
Math and computer tutor/teacher
h(4) = 2(4^2)-4 = 32-4=28
h(5) = 2(5^2)-5 = 50-5 = 45
Net change is 45-28 = 17
AROC = 17/1 = 17
Nia P.
asked 02/21/21Patrick B. answered 02/21/21
Math and computer tutor/teacher
h(4) = 2(4^2)-4 = 32-4=28
h(5) = 2(5^2)-5 = 50-5 = 45
Net change is 45-28 = 17
AROC = 17/1 = 17
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