List three points that lie on the graph of y= 2^x+1

Answer 1

(0,2

(1,3)

(2,5)

let x = 0, then y= 2^0 + 1 = 1+ 1 (any number to the zero power = 1)

let x = 1, then y=2^1 + 1 = 2+ 1 = 3

let x=2, then y= 2^2 + 1 = 4 + 1 = 5