The common base is 3
27= 3^3 and 9= 3^2 so
(3^3)^x-16 = (3^2)^7x+31
3^ 3x-48 = 3^ 14x+62 so
3x-48 = 14x+62
-11x= 110
x=-10
Mona H.
asked 02/20/21Show step by step work:
27x-16=97x+31
The common base is 3
27= 3^3 and 9= 3^2 so
(3^3)^x-16 = (3^2)^7x+31
3^ 3x-48 = 3^ 14x+62 so
3x-48 = 14x+62
-11x= 110
x=-10
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