Yuri O. answered 02/08/21
16 years online, 464 former SAT problems drilled down
Your expression consists of two fractions being added:
(9y + 7)/(y - 3) + (5y + 6)/(y - 3)
(y - 3) is denominator and it cannot equal “0” (“0” in denominator will make a fraction undefined)
y - 3 = 0
y = 3
Answer: “y” cannot equal “3”.