Given that ​g(x)=3x2+3x+6​, find each of the following. ​a) ​g(−4​) ​b) ​g(p+4​)

Answer 1

g(-4) = 3(-4)^2 + 3(-4) + 6 = 3(16) + 3(-4) + 6 = 48-12+6 = 42

G(p+q) = 3(p+q)^2 + 3(p+q) + 6

= 3(p+q) [ p+q + 1] + 6

= 3 [ p^2 + pq + p

+ pq + q^2 + q ] + 6

= 3[ p^2 + 2pq + p + q^2 + q] + 6