SOLVE TRIANGLE ABC

Question

Solve triangle ABC. (If an answer does not exist, enter DNE. Round your answers to one decimal place. Below, enter your answers so that ∠A₁

 is smaller than ∠A₂.)

b = 128,    c = 162,    ∠B = 47°

Answer 1

b= 128, c=162, angleB=47

use law of sines to find angle C

c/SinC = b/SinB = 128/Sin47

SinC = cSin47/128 = 162Sin47/128 = 81Sin47/64= about .926

C = arcsin.933 = about 67.76 degrees

angle A = 180-67.76-47 = 112.24-47 = 64.76 degrees

a = 162sin64.76/sin67.76 = about 158.31

a-b-c = 158.31-128-162

A-B-C = 64.76- 47- 67.76

shortest side is opposite smallest angle

longest side is opposite largest angle

67.76>64.76>47

162>158.31>128