Linux assignment lab question

Question

Using awk, write the command that would print the line that contains the word "selected". This file has a lot of junk in it. So, you are just searching for the lines that contain the word “selected”. Your awk script will look into the file called longfile and once it finds all the lines that contain the word "selected" it will display the line. The output should be:

output: (There should be only one line)

server, or at least to a "randomly" selected one of the servers covering

YOUR AWK COMMAND:

Answer 1

In Awk, there is the operation ~ which checks a string against a regex. Regexes are written as the regex in between two slashes.

And in Awk $1, $2, $3 represent the Nth field in a separated line, while $0 contains the whole line.

So to put this all together, one can print the lines which contain "selected" by using

awk '$0 ~ /selected/' longfile

By default, if there is no command for what to do on a matching line, the line is printed.

If you need to only print the first line with the word "selected", you would need to add the command

# Print the first line matching "selected" and then exit

awk '$0 ~ /selected/ { print $0; exit }' longfile