
Patrick B. answered 03/07/21
Math and computer tutor/teacher
2 | 1 -5 2 8
2 -6 -8
____________________
1 -3 -4 0
and
2^3 - 5(2^2) + 2(2) + 8 =
8 - 5*4 + 4 + 8 =
-12+4+8 = 0
so yes, x=2 is a solution because the remainder is zero
when divided by x-2
x^2-3x-4 = 0
( x - 4)(x + 1 ) = 0
x = 4 or x =-1 are the other two solutions