In the following​ exercise, find the coordinates of the vertex for the parabola defined by the given quadratic function.

Question

f(x)=2(x-4)^2-2

The vertex is ____

​(Type an ordered​ pair.)

Answer 1

This function is in vertex form.

f(x) = a(x - b)^2 + c which gives the vertex as (b,c) because it shifts y = ax^2, which has a vertex at the origin (0,0) to the left or right along the x axis by b units (depending on the sign of b) and up or down c units (depending on the sign of c).

Thus, the vertex here is (4,-2).