Use the rational funcion, g(x)= 1 / -1/3(x-2) - 2 , to answer part a & b.

Question

Part A

Write the equation of the vertical asymptote:

Part B

Write the equation of the horizontal asymptote:

Answer 1

Assuming g(x) = 1/(-(1/3)(x-2)-2). If g(x) = 1/(-(1/3)(x-2)) - 2, then that's a different problem

A) The vertical asymptote is when -(1/3)(x-2)-2) = 0 or x = -4

B) The horizontal asymptote is found when x approaches ±∞

Manipulating g(x):

g(x) = 3/(-x-4) = -3/(x-4)

When ±x is very large, g(x) approaches 0