Raymond B. answered 02/01/21
Math, microeconomics or criminal justice
3(x+5)(x-2)(x^2+16) =
3(x^2+3x-6)(x^2+16) =
3(x^4 +3x^3 + 10x^2 +48x -96) =
3x^4 + 9x^3 +30x^2 +144x - 288
Just take each zero and change its sign, then add an x to it to get the factors, then multiply them all together, along with a 3.
(x-4i)(x+4i) = x^2+16. imaginary roots come in conjugate pairs, You can't have one zero without the other.