Could someone please help?

Question

One number is seven more than the other. Their sum is 33. Find the numbers. (Enter your answers as a comma-separated list.)

Answer 1

20 and 13 sum to 33, difference = 7

x+y = 33

x-y = 7

add the 2 equations

2x = 33+7 = 40

2x = 40

x = 40/2= 20

x+y =33

y = 33-x = 33-20 = 13

x,y = 20,13

or solution to the equations is (x,y) = (20,13)

Answer 2

Let x and y be the numbers. From the description

y = x + 7

x + y = 33

Substitute y = x + 7 into the sum

x + x + 7 = 33 --> 2x = 33-7 --> x = 26/2 --> x = 13

y = x + 7 = 13+7 = 20

The numbers are 13, 20.

Check 13 + 20 = 33