If you evaluate the function at x=0 you get y=3(0)-2(1)=-2 which is <x as x=-2
If you evaluate at x=pi/2you get 3(1)-2(0)=3 which is >pi/2= 1.57
since the function is continuous and it has gone from a value less than x to a value greater than x then it would have to pass through a point where the 2 are equal
If you do the same calculation at x=pi (I will leave this to you) you will see that y=3sinx -2cosx is <pi(3.14). So udon got the same logic it would again have to pass though a second point where they are equal.
So you have proven that there are at least 2 points where the two functions are equal.
You can see this graphically on Desmos
‘graph y= 3sinx-2cosx and y=x and you will see they cross twice in the interval (0 - pi)
Kara S.
Thank you Steven, thats very helpful :-)01/31/21
Stephen K.
01/31/21
Stephen K.
01/31/21