Degree 4; root of multiplicity 2 at x = 4, and roots of multiplicity 1 at x = 1 and x = −2 ; y-intercept at (0, −3).

Answer 1

f(x) = k(x-4)(x-4)(x-1)(x+2)

for some fixed number constant k

f(0)=-3 is given as the y-intercept

of (0,-3)

-3 = f(0) = k(-4)(-4)(-1)(2)

-3 = k(-32)

k = 3/32

Answer 2

f(x) = a(x - 4)(x - 4)(x - 1)(x + 2)

Substitute 3 for x and -3 for f(x) and determine value of a.