The question is in the description. Thank you!

Question

a. A group of friends is going to the movies. Each ticket costs $8.00. Write an equation to model the total cost of the group’s tickets.

b. Graph the equation. Explain what the x- and y- intercepts represent.

c. What would be the cost for 12 tickets?

d. Writing could be the domain include fractions?

Explain.

Answer 1

A) let x represent the number of tickets and y be the total cost of the tickets, then

y= 8x

B) In this case, the x-intercept represents the scenario where the cost is equal to zero- meaning, if the cost is zero, no tickets have been bought.

The y-intercept represents the scenario where the number of tickets are equal to zero- meaning, if no tickets are being bought, then no money is being spent.

C) The cost for twelve tickets would simply be

y=8·12=72

D) The domain (all possible x values that our function could take on) could not be fractions. This is because x is the number of tickets, which can only be represented by strictly whole numbers.

Answer 2

Hello, Adriana,

I'll set x equal to the number of friends going to the movie. We know that each ticket costs $8. Assuming that everyone (x) sees just one move, the total cost would be 8x. It costs $8/friend to get in. So the equation that tells us how much will be spent (before popcorn) is:

y = 8x, where y is the total cost for x friends to see 1 movie.

y = 8x is a straight line. So pick the point (0,0) and one other. I'll pick (5,40). Draw a straight from (0,0) to (5,40) and beyond. The X axis is labelled "Friends," and the Y axis is labelled "Total Cost." The line cannot go below zero, since there are no -1 friends. A negative number such as (-1,-8) would mean that the movie theater paid you $8 for your -1 friend. :)

Technically the answer should read y = 8x for x >= 0. AQnd x will be an integer.

Both the x- and y-intercepts are at (0.0). If no friends see a movie, $0 is spent.

If 12 friends go, the total cost is y = 8*(12)

y = $96

I don't understand the last question, but if asks if fractions are possible, the answer is no, unless you have 1/2 of a friend who could get in for 1/4 the price.

Bob