The stone starts with a velocity of 53 feet per second. It leaves the sling 22 feet below ground level. What is the maximum height that the stone will reach?

Answer 1

-16t^2 + 53t + 22

take the derivative and set = 0

-32t + 53 = 0

t = 53/32= about 1.66 seconds or close to 5/3 seconds

max height = -16(5/3)^2 + 53(5/3) + 22 = -16(25/9) + 265/3 +22 = 395/9 + 22 = 65 8/9 feet

max height = 65.89 feet