The stone starts with a velocity of 53 feet per second. It leaves the sling 22 feet below ground level. What is the maximum height that the stone will reach?

Answer 1

The stone never was able to the ground because it was covered.

Answer 2

We assume the stone is launched vertically up. Ok?

The maximum height is when the velocity becomes 0:

V = 0 = V₀ - g*t

So from this equation you will find t (time to the maximum height):

t = V₀ / g = 53 / 9.8 sec

_{Now, the equation for the coordinate is}

_{h = -22 + V0 * t - g * t^2 / 2}

_{= -22 + 53 * (53/9.8) - 9.8 * (53/9.8)^2 / 2}