Suppose you lean out of a window in a tall building and drop a stone. it leaves your hand 492 feet above the ground. How much time will you be me will it take to hit ground level ?

Answer 1

h(t) = gt²/2 + v₀ + h₀

The initial velocity, v₀ = 0, since the stone was dropped not thrown. The initial height, h₀ = 492 ft.

The problem is wanting the time when the height is ground level = 0. Gravity, g = -32 ft/s².

-16t² + 492 = 0

t² = 492/16 = 30.75

t = √30.75 = 5.545 seconds (taking only the positive value of the square root since this is a measurement)