The stone starts with a velocity of 53 feet per second. It leaves the sling 22 feet below ground level. How much time will it take for the stone to get to its maximum height?

Answer 1

h(t) = -16t^2 + 53t -22 = 0 gives height at time t

take the derivative and set = 0 to solve for t at maximum height

h'(t) = -32t +53 = 0

t= 53/32 seconds when the stone reaches maximum height. 53/32 = about 1.66 seconds = about 1 2/3 sec.