Find cos θ cos θ and sin θ

Question

tanθ=23tanθ=23 and cscθ<0cscθ<0.

Answer 1

23tanT = 23

tanT = 1

T = 45 degrees = pi/4 radians

sinT =cosT = (sqr2)/2 = about .707

but cscT<0 means 3rd quadrant

so sinT=cosT = -(sqr2)/2 = about - .707