Write the equation of a line perpendicular to 3x + 2y = 6 through the point (-6, 2)

Answer 1

3x+2y = 6

2y = -3x + 6

y = -3x/2 + 3

-3/2 is the slope = m

the negative inverse = 2/3

y=(2/3)x + b

2=(2/3)(-6) + b

2 = -4 + b

b = 6

y= (2/3)x + 6 is the perpendicular line through the point (-6,2)